Solving Equations - Algebra II (2024)

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Algebra II Help » Basic Single-Variable Algebra » Equations » Solving Equations

Example Question #1 : Linear Systems With Three Variables

Solve this system of equations.

Solving Equations - Algebra II (1)

Solving Equations - Algebra II (2)

Solving Equations - Algebra II (3)

Possible Answers:

Solving Equations - Algebra II (4), Solving Equations - Algebra II (5), Solving Equations - Algebra II (6)

Solving Equations - Algebra II (7), Solving Equations - Algebra II (8), Solving Equations - Algebra II (9)

Solving Equations - Algebra II (10), Solving Equations - Algebra II (11), Solving Equations - Algebra II (12)

Solving Equations - Algebra II (13), Solving Equations - Algebra II (14), Solving Equations - Algebra II (15)

Solving Equations - Algebra II (16), Solving Equations - Algebra II (17), Solving Equations - Algebra II (18)

Correct answer:

Solving Equations - Algebra II (19), Solving Equations - Algebra II (20), Solving Equations - Algebra II (21)

Explanation:

Equation 1: Solving Equations - Algebra II (22)

Equation 2: Solving Equations - Algebra II (23)

Equation 3: Solving Equations - Algebra II (24)

Adding the terms of the first and second equations together will yield Solving Equations - Algebra II (25).

Then, add that to the third equation so that the y and z terms are eliminated. You will get Solving Equations - Algebra II (26).

This tells us that x = 1. Plug this x = 1 back into the systems of equations.

Solving Equations - Algebra II (27)

Solving Equations - Algebra II (28)

Solving Equations - Algebra II (29)

Now, we can do the rest of the problem by using the substitution method. We'll take the third equation and use it to solve for y.

Solving Equations - Algebra II (30)

Solving Equations - Algebra II (31)

Solving Equations - Algebra II (32)

Plug this y-equation into the first equation (or second equation; it doesn't matter) to solve for z.

Solving Equations - Algebra II (33)

Solving Equations - Algebra II (34)

Solving Equations - Algebra II (35)

Solving Equations - Algebra II (36)

Solving Equations - Algebra II (37)

We can use this z value to find y

Solving Equations - Algebra II (38)

Solving Equations - Algebra II (39)

Solving Equations - Algebra II (40)

So the solution set is x = 1, y = 2, and z = –5/3.

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Example Question #2 : Solving Equations

Solve for Solving Equations - Algebra II (41):Solving Equations - Algebra II (42)

Possible Answers:

Solving Equations - Algebra II (43)

Solving Equations - Algebra II (44)

Solving Equations - Algebra II (45)

Solving Equations - Algebra II (46)

Correct answer:

Solving Equations - Algebra II (47)

Explanation:

To solve this problem we can first addSolving Equations - Algebra II (48)to each side of the equation yieldingSolving Equations - Algebra II (49)

Then we take the square root of both sides to getSolving Equations - Algebra II (50)

Then we calculate the square root ofSolving Equations - Algebra II (51)which isSolving Equations - Algebra II (52).

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Example Question #3 : Solving Equations

Solve this system of equations forSolving Equations - Algebra II (53):

Solving Equations - Algebra II (54)

Solving Equations - Algebra II (55)

Correct answer:

Solving Equations - Algebra II (61)

Explanation:

Multiply the top equation by 3 on both sides, then add the second equation to eliminate theSolving Equations - Algebra II (62)terms:

Solving Equations - Algebra II (63)

Solving Equations - Algebra II (64)

Solving Equations - Algebra II (65)

Solving Equations - Algebra II (66)

Solving Equations - Algebra II (67)

Solving Equations - Algebra II (68)

Solving Equations - Algebra II (69)

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Example Question #91 : Factoring Polynomials

Solve forSolving Equations - Algebra II (70).

Solving Equations - Algebra II (71)

Possible Answers:

Solving Equations - Algebra II (72)

Solving Equations - Algebra II (73)

Solving Equations - Algebra II (74)

Solving Equations - Algebra II (75)

Solving Equations - Algebra II (76)

Correct answer:

Solving Equations - Algebra II (77)

Explanation:

Solving Equations - Algebra II (78)

Multiply both sides by 3:

Solving Equations - Algebra II (79)

Solving Equations - Algebra II (80)

Distribute:

Solving Equations - Algebra II (81)

Subtract Solving Equations - Algebra II (82)from both sides:

Solving Equations - Algebra II (83)

Add the Solving Equations - Algebra II (84)terms together, and subtract Solving Equations - Algebra II (85)from both sides:

Solving Equations - Algebra II (86)

Divide both sides bySolving Equations - Algebra II (87):

Solving Equations - Algebra II (88)

Simplify:

Solving Equations - Algebra II (89)

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Example Question #1 : Solving Equations

Solve for Solving Equations - Algebra II (90):

Solving Equations - Algebra II (91)

Possible Answers:

Solving Equations - Algebra II (92)

Solving Equations - Algebra II (93)

Solving Equations - Algebra II (94)

Solving Equations - Algebra II (95)

Solving Equations - Algebra II (96)

Correct answer:

Solving Equations - Algebra II (97)

Explanation:

Distribute the x through the parentheses:

x2 –2x = x2 – 8

Subtract x2 from both sides:

–2x = –8

Divide both sides by –2:

x = 4

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Example Question #1 : Solving Equations

Solve for Solving Equations - Algebra II (98):.

Solving Equations - Algebra II (99)

Possible Answers:

Solving Equations - Algebra II (100)

Solving Equations - Algebra II (101)

Solving Equations - Algebra II (102)

Solving Equations - Algebra II (103)

Solving Equations - Algebra II (104)

Correct answer:

Solving Equations - Algebra II (105)

Explanation:

First factor the expression by pulling out Solving Equations - Algebra II (106):

Solving Equations - Algebra II (107)

Solving Equations - Algebra II (108)

Factor the expression in parentheses by recognizing that it is a difference of squares:

Solving Equations - Algebra II (109)

Set each term equal to 0 and solve for the x values:

Solving Equations - Algebra II (110)

Solving Equations - Algebra II (111)

Solving Equations - Algebra II (112)

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Example Question #1 : Systems Of Equations

Solve the system of equations.

Solving Equations - Algebra II (113)

Solving Equations - Algebra II (114)

Possible Answers:

Solving Equations - Algebra II (115)

Solving Equations - Algebra II (116)

Solving Equations - Algebra II (117)

Solving Equations - Algebra II (118)

None of the other answers are correct.

Correct answer:

Solving Equations - Algebra II (119)

Explanation:

IsolateSolving Equations - Algebra II (120) in the first equation.

Solving Equations - Algebra II (121)

Plug Solving Equations - Algebra II (122) into the second equation to solve for Solving Equations - Algebra II (123).

Solving Equations - Algebra II (124)

Solving Equations - Algebra II (125)

Solving Equations - Algebra II (126)

Solving Equations - Algebra II (127)

Solving Equations - Algebra II (128)

Plug Solving Equations - Algebra II (129) into the first equation to solve for Solving Equations - Algebra II (130).

Solving Equations - Algebra II (131)

Solving Equations - Algebra II (132)

Solving Equations - Algebra II (133)

Now we have both the Solving Equations - Algebra II (134) and Solving Equations - Algebra II (135) values and can express them as a point: Solving Equations - Algebra II (136).

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Example Question #1 : Solving Equations

Solve forSolving Equations - Algebra II (137) and Solving Equations - Algebra II (138).

Solving Equations - Algebra II (139)

Solving Equations - Algebra II (140)

Possible Answers:

Solving Equations - Algebra II (141)

Solving Equations - Algebra II (142)

Solving Equations - Algebra II (143)

Cannot be determined.

Solving Equations - Algebra II (144)

Correct answer:

Solving Equations - Algebra II (145)

Explanation:

1st equation: Solving Equations - Algebra II (146)

2nd equation: Solving Equations - Algebra II (147)

Subtract the 2nd equation from the 1st equation to eliminate the "2y" from both equations and get an answer for x:

Solving Equations - Algebra II (148)

Plug the value ofSolving Equations - Algebra II (149) into either equation and solve for Solving Equations - Algebra II (150):

Solving Equations - Algebra II (151)

Solving Equations - Algebra II (152)

Solving Equations - Algebra II (153)

Solving Equations - Algebra II (154)

Solving Equations - Algebra II (155)

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Example Question #9 : Solving Equations

What is a solution to this system of equations:

Solving Equations - Algebra II (156)

Possible Answers:

Solving Equations - Algebra II (157)

Solving Equations - Algebra II (158)

Solving Equations - Algebra II (159)

Solving Equations - Algebra II (160)

Solving Equations - Algebra II (161)

Correct answer:

Solving Equations - Algebra II (162)

Explanation:

Step 1:Multiply first equation by2and add the result to the second equation. The result is:

Solving Equations - Algebra II (163)

Step 2:Multiply first equation by3and add the result to the third equation. The result is:

Solving Equations - Algebra II (164)

Step 3:Multiply second equation by23and add the result to the third equation. The result is:

Solving Equations - Algebra II (165)

Step 4:solve forz.

Solving Equations - Algebra II (166)

Solving Equations - Algebra II (167)

Step 5:solve fory.

Solving Equations - Algebra II (168)

Solving Equations - Algebra II (169)

Solving Equations - Algebra II (170)

Step 6:solve forxby substitutingy=2andz=1into the first equation.

Solving Equations - Algebra II (171)

Solving Equations - Algebra II (172)

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Example Question #10 : Solving Equations

What is a solution to this system of equations?

Solving Equations - Algebra II (173)

Possible Answers:

Solving Equations - Algebra II (174)

Solving Equations - Algebra II (175)

Solving Equations - Algebra II (176)

Solving Equations - Algebra II (177)

Solving Equations - Algebra II (178)

Correct answer:

Solving Equations - Algebra II (179)

Explanation:

  1. Solving Equations - Algebra II (180)
  2. Solving Equations - Algebra II (181)

Substitute equation 2. into equation 1.,

Solving Equations - Algebra II (182)

Solving Equations - Algebra II (183)

Solving Equations - Algebra II (184)

so,Solving Equations - Algebra II (185)

Substitute Solving Equations - Algebra II (186)into equation2:

Solving Equations - Algebra II (187)

so, the solution isSolving Equations - Algebra II (188).

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Solving Equations - Algebra II (2024)
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